The JSDoc @type tag allows specification of a variable type, such as /** @type {Number} */. However I've also see /** @type Number */ without the curly braces, and it seems equally valid.  Use JSDoc has an example both with and without the curly...
I have seen a code like this and wonder what that curly brackets for, is it some kind of argumant pass?  <script type="text/javascript" src="some_script.js?{0}"></script>...
I have pored over the formatting settings on Eclipse for hours and found no solution to this problem:  Video of issue  When I type the opening curly brace on the line immediately following an if, else or function line the ending brace is automaticall...
Whereas, in PHP, it's possible to:  <?PHP if($foo) { ?> <strong>only appears if $foo is true.</strong> <?PHP } else { ?> <em>only appears if $foo is false.</em> <?PHP } ?>   Can one, in Javascript, open a...
Is this piece of code:  const a = { aProp: 1 }; const c = {     b: { a } };   the same as this piece of code:  const a = { aProp: 1 }; const c = {     b: a };   ?  I mean will c have exactly the same properties in both cases? And what technical diffe...
I've been trying to use the approach suggested by another SO-User: https://stackoverflow.com/a/1820837/1324861  But without luck. Basically, I have a large JSON Object that I transformed into a string using JSON.stringify() in order to execute a...
When I write JavaScript i like to have the opening brace on a new line. When I create a for loop or if statement for example, I press the return key after the closing '(' then try to put '{' but it is indented like the picture and is...
This is my code:  <script src="jquery-1.11.3.js"></script> <script>      $(document).ready(function() {              $("button").click(function() {      $("#left").css({"border" :...
I'm new to arrow functions in JavaScript.  I have two arrow functions below:  const squareX = x => {     x * x; }  const actuallySquareX = x => x * x;   The function actuallySquareX works perfectly.  The function squareX...
I'm doing FreeCode camp exercises, and this has messed-up my mind:  const squareList = arr =>   arr     .filter(num => num > 0 && num % parseInt(num) === 0)     .map(num => Math.pow(num, 2));  const squaredIntegers = squareLis...

Tags

Recent Questions

Top Questions

Home Tags Terms of Service Privacy Policy DMCA Contact Us

©2020 All rights reserved.