Trying to get the highest and lowest value from an array that I know will contain only integers seems to be harder than I thought.    var numArray = [140000, 104, 99]; numArray = numArray.sort(); alert(numArray)     I'd expect this to show 99,...

How can I generate some unique random numbers between 1 and 100 using JavaScript?...

How do I parse and evaluate a mathematical expression in a string (e.g. '1+1') without invoking eval(string) to yield its numerical value?  With that example, I want the function to accept '1+1' and return 2....

Is there a simple way to format numbers in JavaScript, similar to the formatting methods available in C# (or VB.NET) via ToString("format_provider") or String.Format()?...

I need to show a currency value in the format of 1K of equal to one thousand, or 1.1K, 1.2K, 1.9K etc, if its  not an even thousands, otherwise if under a thousand, display normal 500, 100, 250 etc, using javascript to format the number?...

How can I do the following in JavaScript?   Concatenate "1", "2", "3" into "123" Convert "123" into 123 Add 123 + 100 = 223 Covert 223 into "223"...

I have the following code:  var str = "0x4000000000000000";   //4611686018427387904 decimal var val = parseInt(str); alert(val);   I get this value: "4611686018427388000", which is 0x4000000000000060  I was wondering if JavaScript i...

While working on a project, I came across a JS-script created by a former employee that basically creates a report in the form of  Name : Value Name2 : Value2   etc.  The peoblem is that the values can sometimes be floats (with different precision)...

I am looking for an easy way in JavaScript to check if a number has a decimal place in it (in order to determine if it is an integer).  For instance,  23 -> OK 5 -> OK 3.5 -> not OK 34.345 -> not OK   if(number is integer) {...}...

I have float numbers like 3.2 and 1.6.  I need to separate the number into the integer and decimal part. For example, a value of 3.2 would be split into two numbers, i.e. 3 and 0.2  Getting the integer portion is easy:  n = Math.floor(n);   But I a...