`JavaScript  I've tried searching for something like this, but I am not able to find it.  It's a simple idea:  a. Take a random number between 0 to 10.  b. Let's say the random number rolled is a 3.  c. Then, save the number (the 3).  d....`
`Say, if I wanted to generate an unbiased random number between min and max, I'd do:  var rand = function(min, max) {     return Math.floor(Math.random() * (max - min + 1)) + min; };   But what if I want to generate a random number between min and...`
`In javascript (or jquery) is there a simple function to have four integers with their probability values: 1|0.41, 2|0.29, 3|0.25, 4|0.05  how can I generate these four numbers taking into account their probabilities  ?  This question is very similar...`
`The requirement is to send a unique id to database when user click on submit button. So I am using Javascript Math.random method. I just want to know what are the chances or possibility to get same number and what bit size of using Math.random....`
`Can any of these functions, the standard normal cumulative distribution function, the normal cumulative distribution function, or the error function, be reliably calculated with javascript?  I'd like to have a totally client side solution conside...`
`Using JavaScript or jQuery, I'm trying to create a string generator that relies on dependent probability. For example, if I generated "doctor" on the first go, no other "doctors" would appear. It would go to another url, like "...`
`I have an object like   const data = {     'Washington' : { ElectoralVotes : 12, RChance: 0 },     'Oregon': { ElectoralVotes: 7, RChance: 15 },      .     .     .      'Hawaii' : { ElectoralVotes: 4, RChance : 35 } }   where...`
`Line 6 says it's expecting an identifier. I'm trying to make it so rolling a 1 on either die makes the score 0, and rolling doubles doubles your score, otherwise, the score is the sum of the two die.  var die1 = Math.floor(Math.random()*6 + 1...`
`I have a formula that generates a random integer in a given range [x,y].  rand = Math.floor(x + Math.random()*(y-x+1));   And I would like the generated integer to have a higher chance of being close to the midrange. Here is an interesting approach....`
`In the initial state we've got a list of elements having different weights from zero to one.  let list = [   0.1,   0.83,   0.65,   0.9,   0.23,   0.17,   0.87,   0.34 ];   In the final state we will need to pick only one elem...`