JavaScript  I've tried searching for something like this, but I am not able to find it.  It's a simple idea:  a. Take a random number between 0 to 10.  b. Let's say the random number rolled is a 3.  c. Then, save the number (the 3).  d....
Say, if I wanted to generate an unbiased random number between min and max, I'd do:  var rand = function(min, max) {     return Math.floor(Math.random() * (max - min + 1)) + min; };   But what if I want to generate a random number between min and...
In javascript (or jquery) is there a simple function to have four integers with their probability values: 1|0.41, 2|0.29, 3|0.25, 4|0.05  how can I generate these four numbers taking into account their probabilities  ?  This question is very similar...
The requirement is to send a unique id to database when user click on submit button. So I am using Javascript Math.random method. I just want to know what are the chances or possibility to get same number and what bit size of using Math.random....
Can any of these functions, the standard normal cumulative distribution function, the normal cumulative distribution function, or the error function, be reliably calculated with javascript?  I'd like to have a totally client side solution conside...
Using JavaScript or jQuery, I'm trying to create a string generator that relies on dependent probability. For example, if I generated "doctor" on the first go, no other "doctors" would appear. It would go to another url, like "...
I have an object like   const data = {     'Washington' : { ElectoralVotes : 12, RChance: 0 },     'Oregon': { ElectoralVotes: 7, RChance: 15 },      .     .     .      'Hawaii' : { ElectoralVotes: 4, RChance : 35 } }   where...
Line 6 says it's expecting an identifier. I'm trying to make it so rolling a 1 on either die makes the score 0, and rolling doubles doubles your score, otherwise, the score is the sum of the two die.  var die1 = Math.floor(Math.random()*6 + 1...
I have a formula that generates a random integer in a given range [x,y].  rand = Math.floor(x + Math.random()*(y-x+1));   And I would like the generated integer to have a higher chance of being close to the midrange. Here is an interesting approach....
In the initial state we've got a list of elements having different weights from zero to one.  let list = [   0.1,   0.83,   0.65,   0.9,   0.23,   0.17,   0.87,   0.34 ];   In the final state we will need to pick only one elem...

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