From the MDN docs for the standard setPrototypeOf function  as well as the non-standard  __proto__ property:     Mutating the [[Prototype]] of an object, no matter how this is accomplished, is strongly discouraged, because it is very slow and unavo...

MDN has a huge scary warning about modifying the prototype in your code:      Changing the [[Prototype]] of an object is, by the nature of how   modern JavaScript engines optimize property accesses, a very slow   operation, in every browser and JavaS...

I have got the following prototype chain   SuperSuperClass  SuperClass  Class     each with a method named do.  What is the common approach for calling the respective super class method? For the moment I use <ClassName>.prototype.__proto__.<...

Can I enforce that the prototype of an object not be changed?  Note! There are some requirements:   The object should behave just like a regular object literal (add/remove/configure/modify properties and descriptors on the object), with literally the...

When I execute this in Node 4, the last statement evaluates to true, however in Node 6 it evaluates to false.  Why?  F = () => {}; F.prototype = {}; Object.create(F.prototype) instanceof F;...

A project I'm working on currently has called for an object type Chain that itself produces a type of object Link that only it uses. In previous projects, I had nested the object constructor and prototype of Link inside the constructor for Chain,...

I'm reading a great book called 'Javascript Enlightenment' by Cody Lindley.  In the chapter that covers the prototype property it discusses how a function instance is always given a prototype property...easy enough to understand. The bold...

I've recently found an interest in the factory function pattern in JavaScript. Classes may be pretty clean, but I've found they've got their fair share of issues. (I'm not going to even talk about them because that isn't at all th...

MDN states:     Also, when iterating over the properties of an object, every enumerable property that is on the prototype chain will be enumerated.   So I tried this:  var x = {a: "I am a"}; var z = Object.create(x);  for( i in z ) {     cons...

Consider this code...  var org = {};  org.Organization = function() {      var app = null;     function setupApplication() {};      return {         init : function() {             console.log("init");         }     } };  org.Organization.pro...