I want to create sub-class B that inherits from super-class A. my code here:  function A(){     this.x = 1; }  B.prototype = new A; function B(){     A.call(this);     this.y = 2; } b = new B; Console.log(b.x + " " + b.y );   when run it,it s...
I have just seen a google tech talk presented by John Resig where he said jQuery operates as an array. Following that advice I have been playing with a subclassed array and it works great but I have been looking through the jQuery source and can'...
Problem:  I have a dynamically created HTML table, that is used for filling out time sheets. It is created programmatically - there is no formal control. The design is a mix of CSS with text boxes being created through JavaScript. Now each 'row&#...
In ES6, is there a way to call a parent constructor passing through variadic arguments, a la foo.apply(this, arguments)? I've looked for an answer, and the only instances I see are either calling super() (no arguments) or calling super(x, y) (wit...
I know this is frowned upon, I was just exploring the idea and for the life of me cannot seem to make this work the way I would want it too.  The example should explain all:  String.prototype.MyNS = function() {} String.prototype.MyNS.fooify = functi...
I recently came across this great post by Dr. Axel Rauschmayer:  http://www.2ality.com/2015/02/es6-classes-final.html  The following snippet roughly describes how ECMAScript 6 prototype chains work from an ECMAScript 5 point of view (section 4.2 of t...
I want to create my own RegExp subclass, with additional methods. This is the most simplified version of my approach:  // Declare the subclass function subRegExp(){}  // Inherit from the parent class subRegExp.prototype = new RegExp();  // Create a n...
The problem  I'd like to be able to use classes to create client objects and add address objects to an array within them.  What I'd like to be able to do  let client = new Client ('A123', 'John', 'Smith', avatarUrl); c...

Tags

Recent Questions

Top Questions

Home Tags Terms of Service Privacy Policy DMCA Contact Us

©2020 All rights reserved.