I've read over several examples of code using JavaScript generators such as this one.  The simplest generator-using block I can come up with is something like:  function read(path) {     return function (done) {         fs.readFile(path, "f...
I've got this recursive generator    var obj = [1,2,3,[4,5,[6,7,8],9],10]  function *flat(x) {     if (Array.isArray(x))         for (let y of x)             yield *flat(y)     else         yield 'foo' + x;  }  console.log([...flat(obj)])...
When passing parameters to next() of ES6 generators, why is the first value ignored? More concretely, why does the output of this say x = 44 instead of x = 43:  function* foo() {     let i = 0;     var x = 1 + (yield "foo" + (++i));     conso...
The ES6 method: iterator.throw(err) is often described as injecting an exception as though it occurred at the yield statement in the generator.  The problem is that the stack trace for this exception does not contain any reference to the file/line fo...
Consider this python code  it = iter([1, 2, 3, 4, 5])  for x in it:     print x     if x == 3:         break  print '---'  for x in it:     print x   it prints 1 2 3 --- 4 5, because the iterator it remembers its state across the loops. When...
The following code... Assume that the yield is inside a generator function and that something and else are defined, etc.  const value = something || yield else();   ...produces the following in V8 (Chrome or Nodejs):                  const start = in...
I'm writing some node.js to interact with sensors over a serial port connection.  The code for reading the sensor is asynchronous, naturally.  In my control code, though, I need to read a sensor, do something based on the value, read again, do so...
I have written a simple generator:  function geni() {     for(var i = 0; i < 10; i++)     {         yield i;     } }   And I get the error as below:      SyntaxError: missing ; before statement   [Break On This Error]           yield i;   Browser:...
I have a piece of code:  function * input(){     let array = [];     while(true) {         array.push(yield array);     } }  var gen = input(); console.log(gen.next("A")) console.log(gen.next("B")) console.log(gen.next("C")) c...
Here is my simplified code:  <html> <body>     <button onclick="testRun()">Click me</button>     <script type="application/javascript" language='javascript1.7'>         function testRun() {...

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