javascript sort of HTML elements

I'm trying to sort an li elements and get an unexpacted result I need to sort it three times to get it correctly,

where have I mistaken? javascript

var sort_by_name = function(a, b) {
    return a.innerHTML.toLowerCase() > b.innerHTML.toLowerCase();
}
$this = $("ol#table1");
var list = $this.children();
list.sort(sort_by_name);
console.log(list);
$this.html(list);

HTML

<ol id="table1" style="display: block; ">
   <li class="menu__run">I</li>
   <li class="menu__run">IXX</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li> 
   <li class="menu__run">IXX</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li>
   <li class="menu__run">I</li>
   <li class="menu__test">st</li>
   <li class="menu__test">st</li>
   <li class="menu__test">st</li>
</ol>

fiddle example

Answers:

Answer

There are much better ways to sort.

  1. You need a comparison function that returns the right values: -1, 0, and 1.
  2. localeCompare() is such a comparison function.
  3. You can just move the DOM elements around rather than regenerating the HTML.
  4. You can get the LI elements directly in the original selector.
  5. "#table1" is a more efficient selector than "ol#table1".

I would suggest this:

$("div#btn").click(function() {
    var sort_by_name = function(a, b) {
        return a.innerHTML.toLowerCase().localeCompare(b.innerHTML.toLowerCase());
    }

    var list = $("#table1 > li").get();
    list.sort(sort_by_name);
    for (var i = 0; i < list.length; i++) {
        list[i].parentNode.appendChild(list[i]);
    }
});?

Which you can see work here: http://jsfiddle.net/jfriend00/yqd3w/

Answer

A custom compareFunction needs to return -1, 0 or 1.

function sort_by_name(a, b) {
    var sa = a.innerHTML.toLowerCase(), sb = b.innerHTML.toLowerCase();
    return sb<sa ? -1 : sb>sa ? 1 : 0;
}
Answer
var sort_by_name = function(a, b) {
    return $(a).text().toLowerCase().localeCompare($(b).text().toLowerCase());
}

You can use localeCompare instead to make things more elegant and workable.

See jsfiddle http://jsfiddle.net/Qww87/11/

Answer

according to documentation it needs numeric values. more intelligible:

    var sort_by_name = function(a, b) {
         if(a.innerHTML.toLowerCase() < b.innerHTML.toLowerCase()) return -1;
         if(a.innerHTML.toLowerCase() > b.innerHTML.toLowerCase()) return 1;
         return 0;
    }
Answer

Use my jquery plugin Sort Content :

   $('ol#table1').sortContent({asc:true})

That's it!

DEMO : http://jsfiddle.net/abdennour/SjWXU/

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