Regular expression for number with length of 4, 5 or 6

I need a regular expression that validate for a number with length 4, 5, 6

I used ^[0-9]{4} to validate for a number of 4, but I do not know how to include validation for 5 and 6.



Try this:


{4,6} = between 4 and 6 characters, inclusive.


Be aware that, as written, Peter's solution will "accept" 0000. If you want to validate numbers between 1000 and 999999, then that is another problem :-)


for example will block inserting 0 at the beginning of the string.

If you want to accept 0 padding, but only up to a lengh of 6, so that 001000 is valid, then it becomes more complex. If we use look-ahead then we can write something like


This first checks if the string is long 4-6 (?=[0-9]{4,6}$), then skips the 0s 0*and search for a non-zero [1-9] followed by at least 3 digits [0-9]{3,}.


[0-9]{4,6} can be shortened to \d{4,6}


If the language you use accepts {}, you can use [0-9]{4,6}.

If not, you'll have to use [0-9][0-9][0-9][0-9][0-9]?[0-9]?.


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