Javascript regular expression for punctuation (international)?

I need a regular expression to match against all punctuation marks, such as the standard [,[email protected]#$%^&*()], but including international marks like the upside-down Spanish question mark, Chinese periods, etc. My google-fu is coming up short. Does anyone have such a regular expression on hand that's compatible with Javascript?

Answers:

Answer

If it's possible for you to use a plugin, there is a plugin for JavaScript: XRegExp Unicode plugins. That adds support for Unicode categories, scripts, and blocks (I personally have only read about it, I never used it).

With this plugin it should be possible to use Unicode categories like \p{P} as explained at regular-expressions.info.

Update: OK, I tested it, and it seems to work fine.

You need to get the lib from XRegExp and additionally the Unicode Base and Unicode Category plugins (linked above).

<script src="xregexp.js"></script>
<script src="addons/unicode-base.js"></script>
<script src="addons/unicode-categories.js"></script>
<script>
    var unicodePunctuation = XRegExp("^\\p{P}+$");

    alert(unicodePunctuation.test("?.,;!¡¿??·")); // true
</script>

The above alerts true. I included some Spanish and Chinese punctuation in my test string, "?.,;!¡¿??·".

Answer

Adding to @stema's answer (https://stackoverflow.com/a/7578937/114140)... here is the regex as a string (so you don't need to bloat your project with XRegExp).

!-#%-\x2A,-/:;\[email protected]\x5B-\x5D_\x7B}\u00A1\u00A7\u00AB\u00B6\u00B7\u00BB\u00BF\u037E\u0387\u055A-\u055F\u0589\u058A\u05BE\u05C0\u05C3\u05C6\u05F3\u05F4\u0609\u060A\u060C\u060D\u061B\u061E\u061F\u066A-\u066D\u06D4\u0700-\u070D\u07F7-\u07F9\u0830-\u083E\u085E\u0964\u0965\u0970\u0AF0\u0DF4\u0E4F\u0E5A\u0E5B\u0F04-\u0F12\u0F14\u0F3A-\u0F3D\u0F85\u0FD0-\u0FD4\u0FD9\u0FDA\u104A-\u104F\u10FB\u1360-\u1368\u1400\u166D\u166E\u169B\u169C\u16EB-\u16ED\u1735\u1736\u17D4-\u17D6\u17D8-\u17DA\u1800-\u180A\u1944\u1945\u1A1E\u1A1F\u1AA0-\u1AA6\u1AA8-\u1AAD\u1B5A-\u1B60\u1BFC-\u1BFF\u1C3B-\u1C3F\u1C7E\u1C7F\u1CC0-\u1CC7\u1CD3\u2010-\u2027\u2030-\u2043\u2045-\u2051\u2053-\u205E\u207D\u207E\u208D\u208E\u2329\u232A\u2768-\u2775\u27C5\u27C6\u27E6-\u27EF\u2983-\u2998\u29D8-\u29DB\u29FC\u29FD\u2CF9-\u2CFC\u2CFE\u2CFF\u2D70\u2E00-\u2E2E\u2E30-\u2E3B\u3001-\u3003\u3008-\u3011\u3014-\u301F\u3030\u303D\u30A0\u30FB\uA4FE\uA4FF\uA60D-\uA60F\uA673\uA67E\uA6F2-\uA6F7\uA874-\uA877\uA8CE\uA8CF\uA8F8-\uA8FA\uA92E\uA92F\uA95F\uA9C1-\uA9CD\uA9DE\uA9DF\uAA5C-\uAA5F\uAADE\uAADF\uAAF0\uAAF1\uABEB\uFD3E\uFD3F\uFE10-\uFE19\uFE30-\uFE52\uFE54-\uFE61\uFE63\uFE68\uFE6A\uFE6B\uFF01-\uFF03\uFF05-\uFF0A\uFF0C-\uFF0F\uFF1A\uFF1B\uFF1F\uFF20\uFF3B-\uFF3D\uFF3F\uFF5B\uFF5D\uFF5F-\uFF65

I used this in my own project with some additions...

    // any kind of punctuation character (including international e.g. Chinese and Spanish punctuation)
    // author: http://www.regular-expressions.info/unicode.html
    // source: https://github.com/slevithan/xregexp/blob/41f4cd3fc0a8540c3c71969a0f81d1f00e9056a9/src/addons/unicode/unicode-categories.js#L142
    // note: XRegExp unicode output taken from http://jsbin.com/uFiNeDOn/3/edit?js,console (see chrome console.log), then converted back to JS escaped unicode here http://rishida.net/tools/conversion/, then tested on http://regexpal.com/
    // suggested by: https://stackoverflow.com/a/7578937
    // added: extra characters like "$", "\uFFE5" [yen symbol], "^", "+", "=" which are not consider punctuation in the XRegExp regex (they are currency or mathmatical characters)
    // added: \u3000-\u303F Chinese Punctuation for good measure
    var regex_characters_to_remove = /[\$\uFFE5\^\+=`~<>{}\[\]|\u3000-\u303F!-#%-\x2A,-/:;\[email protected]\x5B-\x5D_\x7B}\u00A1\u00A7\u00AB\u00B6\u00B7\u00BB\u00BF\u037E\u0387\u055A-\u055F\u0589\u058A\u05BE\u05C0\u05C3\u05C6\u05F3\u05F4\u0609\u060A\u060C\u060D\u061B\u061E\u061F\u066A-\u066D\u06D4\u0700-\u070D\u07F7-\u07F9\u0830-\u083E\u085E\u0964\u0965\u0970\u0AF0\u0DF4\u0E4F\u0E5A\u0E5B\u0F04-\u0F12\u0F14\u0F3A-\u0F3D\u0F85\u0FD0-\u0FD4\u0FD9\u0FDA\u104A-\u104F\u10FB\u1360-\u1368\u1400\u166D\u166E\u169B\u169C\u16EB-\u16ED\u1735\u1736\u17D4-\u17D6\u17D8-\u17DA\u1800-\u180A\u1944\u1945\u1A1E\u1A1F\u1AA0-\u1AA6\u1AA8-\u1AAD\u1B5A-\u1B60\u1BFC-\u1BFF\u1C3B-\u1C3F\u1C7E\u1C7F\u1CC0-\u1CC7\u1CD3\u2010-\u2027\u2030-\u2043\u2045-\u2051\u2053-\u205E\u207D\u207E\u208D\u208E\u2329\u232A\u2768-\u2775\u27C5\u27C6\u27E6-\u27EF\u2983-\u2998\u29D8-\u29DB\u29FC\u29FD\u2CF9-\u2CFC\u2CFE\u2CFF\u2D70\u2E00-\u2E2E\u2E30-\u2E3B\u3001-\u3003\u3008-\u3011\u3014-\u301F\u3030\u303D\u30A0\u30FB\uA4FE\uA4FF\uA60D-\uA60F\uA673\uA67E\uA6F2-\uA6F7\uA874-\uA877\uA8CE\uA8CF\uA8F8-\uA8FA\uA92E\uA92F\uA95F\uA9C1-\uA9CD\uA9DE\uA9DF\uAA5C-\uAA5F\uAADE\uAADF\uAAF0\uAAF1\uABEB\uFD3E\uFD3F\uFE10-\uFE19\uFE30-\uFE52\uFE54-\uFE61\uFE63\uFE68\uFE6A\uFE6B\uFF01-\uFF03\uFF05-\uFF0A\uFF0C-\uFF0F\uFF1A\uFF1B\uFF1F\uFF20\uFF3B-\uFF3D\uFF3F\uFF5B\uFF5D\uFF5F-\uFF65]+/g
Answer

Well... idk how extensive it would be, but you could use this:

[^\w\s\n\t]
Answer

Your regex would look something like...

/[,[email protected]#$%^&*()\u9999]/

Where you replace each \u9999 with the Unicode codepoint for the other punctuation characters.

If you could find a bunch in a range, you could specify that with the - range operand, e.g. \u9990-\u9999.

As far as I know you can't use something like \pP in JavaScript regexes.

Answer

For Python this regex to remove from the start and end any type of punctuation marks:

import re
def cleanspecialcharacters(str):   
    regex = re.compile((
    '^[/\"_\(\)&*\$?\^\+=`~<>\{\}\[\]\|\-!#%\,\:;@¡§«¶·»¿???-????????????-???-????-?????-??-??‰-??-??-????????-???-????????-??-??-??????-??-??-??????-?????-?????]*|'
    '([/\"_\(\)&*\$?\^\+=`~<>\{\}\[\]\|\-!#%\,\:;@¡§«¶·»¿???-????????????-???-????-?????-??-??‰-??-??-????????-???-????????-??-??-??????-??-??-??????-?????-?????])*$'))
    str = regex.sub('', str)
    return str

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