In a Node.js module I'm writing I would like to open a file--i.e, with
fs.readFile()--that is contained in the same directory as my module. By which I mean it is in the same directory as the
It looks like all relative path operations which are performed by the
fs module take place relative to the directory in which Node.js is started. As such, I think I need to know how to get the path of the current Node.js module which is executing.
As david van brink mentioned in the comments, the correct solution is to use
__dirname. This global variable will return the path of the currently executing script (i.e. you might need to use
../ to reach the root of your module).
var path = require("path"); require(path.join(__dirname, '/models'));
Just to save someone from a headache.
©2020 All rights reserved.