value = value.replace(/[\r\n]*/g, "");
but when the code actually contains \r\n text what do I do to trim it without affecting r's and n's in my content? I've tried this code:
value = value.replace(/[\\r\\n]+/g, "");
on this bit of text:
I end up with this:
Side note: It leaves the upper case versions of R and N alone because I didn't include the /i flag at the end and thats ok in this case.
What do I do to just remove \r\n text found in the string?
If you want to match literal
\r and literal
\n then you should use the following:
value = value.replace(/(?:\\[rn])+/g, "");
You might think that matching literal
[\\r\\n] is the right way to do it and it is a bit confusing but it won't work and here is why:
Remember that in character classes, each single character represents a single letter or symbol, it doesn't represent a sequence of characters, it is just a set of characters.
So the character class
[\\r\\n] actually matches the literal characters
n as separate letters and not as sequences.
Edit: If you want to replace all carriage returns
\n and also literal
\r and '\n` then you could use:
value = value.replace(/(?:\\[rn]|[\r\n]+)+/g, "");
(?:) it means a non-capturing group, because by default when you put something into a usual group
() then it gets captured into a numbered variable that you can use elsewhere inside the regular expression itself, or latter in the matches array.
(?:) prevents capturing the value and causes less overhead than
(), for more info see this article.
If you have text with a lot of \r\n and want to save all of them try this one
To just remove them, this seems to work for me:
value = value.replace(/[\r\n]/g, "");
You don't need the
* after the character set because the
g flag solves that for you.
Note, this will remove all
\n chars whether they are in this exact sequence or not.
Working demo of this option: http://jsfiddle.net/jfriend00/57GtJ/
If you want to remove these characters only when in this exact sequence (e.g. only when a
\r is directly followed by a
\n, you could use this:
value = value.replace(/\r\n/g, "");
Working demo of this option: http://jsfiddle.net/jfriend00/Ta3sn/
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