'Freezing' Arrays in Javascript?

Since the ECMA-262 specifications Javascript has gained the Object.freeze() method, which allows for objects, whose properties can not be changed, added or removed.

var obj = {'a':1, 'b:2'};
Object.isFrozen(obj);       // returns true
obj.a = 10;                 // new assignment has no affect
obj.a;                      // returns 1

So far so good.

I am wondering, whether freeze() should also work on Arrays.

var arr = [1, 2];
Object.isFrozen(arr);      // returns true
arr[0] = 10;
arr;                       // returns [10, 2] ... ouch!

Maybe I am wrong, but I was under the impression, that Array inherits from Object.

typeof obj                 // "object"
typeof arr                 // "object"

Any ideas, pointers, enlightenments would be highly appreciated.



Yes, freeze should work for Arrays, the behavior you are experiencing is clearly an implementation bug.

This bug might be related to the fact that array objects implement a custom [[DefineOwnProperty]] internal method (the magic that makes the length property work).

I just tested it on two implementations and it works properly (Chrome 16.0.888, and Firefox Aurora 8.02a).

About your second question, well, array objects inherit from Array.prototype which inherits from Object.prototype, for example, you can access non shadowed methods from Object.prototype directly on array objects:

['a'].hasOwnProperty('0'); // true

But this isn't related about how the typeof works, this operator will return 'object' for any object intance, regardless its kind, and for the null value, which people has always complained about.

The rest of possible return values of the typeof operator, correspond to the primitive types of the language, Number, String, Boolean, Symbol and Undefined.


Instead of freeze, use spread operator to copy things without modifying them (if you are using a transpiler, of course):

const second = {
  test: 20

Yes, it is applicable to arrays too.

const arr = [1,2,3,4];
Object.isFrozen(arr)// true
arr.push(5) // you will get a type error
arr.pop() // you will get a type error


Recent Questions

Top Questions

Home Tags Terms of Service Privacy Policy DMCA Contact Us

©2020 All rights reserved.