# round up nearest 0.10

I need to round up to the nearest 0.10 with a minimum of 2.80

`````` var panel;
if (routeNodes.length > 0 && (panel = document.getElementById('distance')))
{
panel.innerHTML = (dist/1609.344).toFixed(2) + " miles = &#163;" + (((dist/1609.344 - 1) * 1.20) + 2.80).toFixed(2);
}
``````

any help would be appreciated

``````var number = 123.123;

Math.max( Math.round(number * 10) / 10, 2.8 ).toFixed(2);
``````

If you need to round up, use Math.ceil:

``````Math.max( Math.ceil(number2 * 10) / 10, 2.8 )
``````

Multiply by 10, then do your rounding, then divide by 10 again

``````(Math.round(12.362 * 10) / 10).toFixed(2)
``````

Another option is:

``````Number(12.362.toFixed(1)).toFixed(2)
``````

``````var panel;
if (routeNodes.length > 0 && (panel = document.getElementById('distance')))
{
panel.innerHTML = Number((dist/1609.344).toFixed(1)).toFixed(2)
+ " miles = &#163;"
+ Number((((dist/1609.344 - 1) * 1.20) + 2.80).toFixed(1)).toFixed(2);
}
``````

To declare a minimum, use the `Math.max` function:

``````var a = 10.1, b = 2.2, c = 3.5;
alert(Math.max(b, 2.8)); // alerts 2.8 because it is larger than b (2.2);
``````

This is a top hit on google for rounding in js. This answer pertains more to that general question, than this specific one. As a generalized rounding function you can inline:

`const round = (num, grainularity) => Math.round(num / grainularity) * grainularity;`

Test it out below:

``````const round = (num, grainularity) => Math.round(num / grainularity) * grainularity;

const test = (num, grain) => {
console.log(`Rounding to the nearest \${grain} for \${num} -> \${round(num, grain)}`);
}

test(1.5, 1);
test(1.5, 0.1);
test(1.5, 0.5);
test(1.7, 0.5);
test(1.9, 0.5);
test(-1.9, 0.5);
test(-1.2345, 0.214);``````

``````var miles = dist/1609.344
miles = Math.round(miles*10)/10;
miles = miles < 2.80 ? 2.80 : miles;
``````

to round to nearest 0.10 you can multiply by 10, then round (using `Math.round`), then divide by 10

Round to the nearest tenth:

``````Math.max(x, 2.8).toFixed(1) + '0'
``````

Round up:

``````Math.max(Math.ceil(x * 10) / 10, 2.8).toFixed(2)
``````