Adjust size of an SVG-element to its content

I would like to adjust the dimensions of a SVG-Element to its content.

JSfiddle: http://jsfiddle.net/4pD9N/

Here I got an example. The SVG should 'shrink' to fit to the elements + 10px margin on each side. In other words: I want to crop the svg for the unused space...

I know that I have to use getBBox. But how can I calculate the total width and height?

Answers:

Answer

By default, the origin of the SVG drawing is the same as the origin of the container. It means that the (0,0) of your drawing is in the upper left corner of the SVG element. To center the content, you should translate the drawing relatively to the container. It can be achieved by modifying the viewBox attribute (four values expected : "minx miny width height") of the SVG element with respect to the result of the getBBox() method. A live example at http://jsfiddle.net/3cp3c/.

svg.setAttribute("viewBox", (bbox.x-10)+" "+(bbox.y-10)+" "+(bbox.width+20)+" "+(bbox.height+20));
svg.setAttribute("width", (bbox.width+20)  + "px");
svg.setAttribute("height",(bbox.height+20) + "px");
Answer
var svg = document.getElementsByTagName("svg")[0];
var bb=svg.getBBox();
var bbx=bb.x;
var bby=bb.y;
var bbw=bb.width;
var bbh=bb.height;
var vb=[bbx,bby,bbw,bbh];
svg.setAttribute("viewBox", vb.join(" ") );

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