Setting the value of a hidden input

The idea: I'm setting the value of an input with type="hidden" via regular Javascript or jQuery.

The issue: neither jQuery nor document.getElementById will find the hidden input, even though I'm absolutely sure the selector is correct and there are no conflicting elements.

The code: I can't really post much of it, because it's full of rather complicated PHP that confuses me when I just look at it.

Here's the javascript:

$("#" +,2) + "_budget_hidden").val(budg_total);

Note: there's nothing wrong with the selector, and the "input" is a different element that I'm using to reference the hidden.

Here's the HTML:

<input type="hidden" name="s<?=$step_counter?>_budget_hidden" 
       id="s<?=$step_counter?>_budget_hidden" value="0" />

The code is kind of out of context, but it's more of a general problem with Javascript than a syntactical error. Thoughts?



In $("#" +,2) + "_budget_hidden").val(budg_total); you take two chars before the first underscore in your hidden id. However your hidden id have only one char 's'


Ok the <?= ?> was hidden before the question edit.

Do you call your script after the body onload event? EX:

    $("#" +,2) + "_budget_hidden").bind("keyPressed",function(){
        $("#" +,2) + "_budget_hidden").val(budg_total);

FYI: We can get the hidden input value using jQuery, even we can also edit any hidden input value using jQuery.

I think your way of getting the hidden value using 'substr' method is causing some problem. You are using like substr(0, 2) so are sure that the variable $step_variable is a single digit number, otherwise your code will not return correct result.

I am giving some sample code below, check it once.

Here's the javascript:

    var input_id = $("hidden_val").attr("id").substr(1);
    $("#" + input_id + "_budget_hidden").val(budg_total);

Here's the HTML:

    input type="hidden" class="hidden_val" name="s_budget_hidden" id="s" value="0" 

I think this will help you. Let me know if you are not following this flow to solve your issue.


I think that,2) says to start at the start of the string, take 2 characters and use that.

Try using Firebug to see what the result of that method call is.


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