gulp.watch does not run tasks in order

Objective

Create a gulp.watch task to run others tasks in a specific order

Why this is not a duplicate

Many people have suggested I take a look at How to run Gulp tasks sequentially one after the other. However, this question focuses on gulp.task while my question focuses on gulp.watch.

The solution I am searching is a way to use gulp.watch to achieve the synchronous effect I am after. If this is not possible however, I will fall-back to gulp.task.

Background

I have a small project, I have some test files as well as the the gulp gulp-complexity plugin. I wish to run the test files first, and then run the gulp-complexity plugin every time a JavaScript file is changed.

What I have tried

I read the documentation and saw the following tutorials:

They were very good, but I still don't understand how I can have a gulp.watch task that runs tasks in synchronously (in a specific order) instead of running them asynchronously.

Code

This is what I got so far:

var gulp = require("gulp");
var mocha = require("gulp-mocha");
var complexity = require("gulp-complexity");

gulp.task("test", function(){
    gulp
    .src("./test.js")
    .pipe(mocha())
    .on("error", function(){
        this.emit("end");
    });
});


gulp.task("complexity", ["test"], function(){
    gulp.src('*.js').pipe(complexity());
});

gulp.task("watch", function(){
    gulp.watch("./*.js", ["test", "complexity"]);
});

What am I doing wrong here?

Please bare in mind I am still very new to gulp (started learning it today!) so any explanations on my problem would be welcome!

Answers:

Answer

This is a Gulp issue and should be be fixed in gulp 4.0

For now, try run-sequence [ https://www.npmjs.com/package/run-sequence ]

Tags

Recent Questions

Top Questions

Home Tags Terms of Service Privacy Policy DMCA Contact Us

©2020 All rights reserved.