I came across the following line

```
hsb.s = max != 0 ? 255 * delta / max : 0;
```

What do the `?`

and `:`

mean in this context?

It is called the Conditional Operator (which is a ternary operator).

It has the form of: `condition`

? `value-if-true`

: `value-if-false`

Think of the `?`

as "then" and `:`

as "else".

Your code is equivalent to

```
if (max != 0)
hsb.s = 255 * delta / max;
else
hsb.s = 0;
```

Properly parenthesized for clarity, it is

```
hsb.s = (max != 0) ? (255 * delta / max) : 0;
```

meaning return either

`255*delta/max`

if max != 0`0`

if max == 0

This is probably a bit clearer when written with brackets as follows:

```
hsb.s = (max != 0) ? (255 * delta / max) : 0;
```

What it does is evaluate the part in the first brackets. If the result is true then the part after the ? and before the : is returned. If it is false, then what follows the : is returned.

hsb.s = max != 0 ? 255 * delta / max : 0;

? is a ternary operator, it works like an if in conjunction with the :

!= means not equals

So, the long form of this line would be

```
if (max != 0) { //if max is not zero
hsb.s = 255 * delta / max;
} else {
hsb.s = 0;
}
```

`? :`

isn't this the ternary operator?

`var x= expression ? true:false`

?: is a short-hand condition for `else {}`

and `if(){}`

problems.
So your code is interchangeable to this:

```
if(max != 0){
hsb.s = 225 * delta / max
}
else {
hsb.s = 0
}
```

Be careful with this. A -1 evaluates to true although -1 != true and -1 != false. Trust me, I've seen it happen.

so

-1 ? "true side" : "false side"

evaluates to "true side"

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