# JavaScript Number Split into individual digits

Hi I am trying to solve a math problem where I take a number e.g. 45, or 111 and then split the number into separate digits e.g. 4 5 or 1 1 1. I will then save each number to a var to run a method on. Does anyone no how to split a number into indivdual digitals.

For example I have a loop that runs on an array :

``````for (var i = 0; i < range.length; i++) {
var n = range[i];
}
``````

For each number I would like to split its digits and add them together ? I will provide a variation on an answer already given so you can see a different approach that preserves the numeric type all along:

``````var number = 12354987,
output = [];

while (number) {
output.push(number % 10);
number = Math.floor(number/10);
}

console.log(output.reverse().join(',')); // 1,2,3,5,4,9,8,7
``````

I've used a technique such as the above to good effect when converting a number to Roman numerals, which is one of my favorite ways to begin to learn a programming language I'm not familiar with. For instance here is how I devised a way to convert numbers to Roman numerals with Tcl slightly after the turn of the century: http://code.activestate.com/recipes/68379-conversion-to-roman-numerals/

The comparable lines in my Tcl script being:

``````  while {\$arabic} {
set digit [expr {\$arabic%10}]
set arabic [expr {\$arabic/10}]
`````` You can work on strings instead of numbers to achieve this. You can do it like this

``````(111 + '').split('')
``````

This will return an array of strings `['1','1','1']` on which you can iterate upon and call `parseInt` method.

``````parseInt('1') === 1
``````

If you want the sum of individual digits, you can use the reduce function (implemented from Javascript 1.8) like this

``````(111 + '').split('').reduce(function(previousValue, currentValue){
return parseInt(previousValue,10) + parseInt(currentValue,10);
})
`````` I used this simple way of doing it.

To split digits

``````var N = 69;
var arr = N.toString().split('').map(Number)
// outputs [6,9]
console.log( arr );
``````

``````console.log(arr.reduce( (a,b) => a+b )); // 15
`````` Separate each 2 parametr.

``````function separator(str,sep) {
var output = '';
for (var i = str.length; i > 0; i-=2) {
var ii = i-1;
if(output) {
output = str.charAt(ii-1)+str.charAt(ii)+sep+output;
} else {
output = str.charAt(ii-1)+str.charAt(ii);
}
}
return output;
}
console.log(separator('123456',':')); //Will return 12:34:56
`````` Shadow Wizard , extended version by Orien

``````var num:Number = 1523;
var digits:Array = [];
var cnt:int = 0;
while (num > 0) {
var mod:int = num % 10;
digits.push(mod * Math.pow(10, cnt))

num = Math.floor(num / 10);
cnt++;
}
digits.reverse();
trace(digits);
``````

output:1000,500,20,3 Without converting to string:

``````function toDigits(number) {
var left;
var results = [];

while (true) {
left = number % 10;
results.unshift(left);
number = (number - left) / 10;
if (number === 0) {
break;
}
}

return results;
}
`````` And the easiest.... `num_string.split('').map(Number)`

Try below:

``console.log((''+123).split('').map(Number))`` With ES6, you could use `Array.from` with a stringed number as iterables and `Number` as mapping function.

``````const getDigits = n => Array.from(n.toString(), Number);

console.log(getDigits(12345));`````` A fun introduction to recursion. This answer takes a Number and returns an array of Number digits. It does not convert the number to a string as an intermediate step.

Given `n = 1234`,

• `n % 10` will return first (right-moist) digit, `4`
• `n / 10` will return `123` with some remainder
• Using `Math.floor` we can chop the remainder off
• Repeating these steps, we can form the entire result

Now we just have to build the recursion condition,

• If the number is already a single digit (n < 10), return an array singleton of the digit
• otherwise (inductive) the number is 10 or greater; recur and prepend to the first digit

``````const digits = (n = 0) =>
n < 10
? [ n ]
: [ ... digits (Math.floor (n / 10)), n % 10 ]

console.log (digits ())        // [ 0 ]
console.log (digits (1))       // [ 1 ]
console.log (digits (12))      // [ 1, 2 ]
console.log (digits (123))     // [ 1, 2, 3 ]
console.log (digits (11234))   // [ 1, 2, 3, 4 ]

console.log (digits (123456789012))
// [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2 ]`````` ``````var num = 111,
separateDigits = num.toString().split(""), i, l = separateDigits.length;

for( i = 0; i < l; ++i ) {
someObject.someMethod( +separateDigits[i] );
}
`````` You can try this.

``````  var num = 99;

num=num.toString().split("").map(value=>parseInt(value,10)); //output [9,9]
``````

Hope this helped! To just split an integer into its individual digits in the same order, Regular Expression is what I used and prefer since it prevents the chance of loosing the identity of the numbers even after they have been converted into string.

The following line of code convert the integer into a string, uses regex to match any individual digit inside the string and return an array of those, after which that array is mapped to be converted back to numbers.

`const digitize = n => String(n).match(/\d/g).map(Number);` `('' + 123456789).split('').map( x => +x ).reduce( (a,b) => a+b ) === 45`

true

or without map

`('' + 123456789).split('').reduce( (a,b) => (+a)+(+b) ) === 45`

true You can do it in single line, seperate each digits than add them together :

``````var may = 12987;
var sep = (""+may).split("").map(n=>+n).reduce((a,b)=>a+b);
`````` This is my short solution.. with sum of number

``````    function sum (num) {
let sNumber = num
.toString()
.split('')
.reduce((el1, el2) => {
return Number(el1) + Number(el2)
}, 0)
return sNumber
}
``````

console.log(sum(123))
console.log(sum(456)) javascript has a function for it and you can use it easily.

``````console.log(new Intl.NumberFormat().format(number));
``````

for example :

``````console.log(new Intl.NumberFormat().format(2334325443534));
==> 2,334,325,443,534
`````` This also works:

``````var number = 12354987;
console.log(String(number).split('').map(Number));`````` ``````var number = 12354987,
output = [],
sNumber = number.toString();

for (var i = 0, len = sNumber.length; i < len; i += 1) {
output.push(+sNumber.charAt(i));
}

console.log(output);

/* Outputs:
*
* [1, 2, 3, 5, 4, 9, 8, 7]
*/
``````

UPDATE: Calculating a sum

``````for (var i = 0, sum = 0; i < output.length; sum += output[i++]);
console.log(sum);

/*
* Outputs: 39
*/
`````` ``````var num = 123456;
var digits = num.toString().split('');
var realDigits = digits.map(Number)
console.log(realDigits);`````` You can also do it in the "mathematical" way without treating the number as a string:

``````var num = 278;
var digits = [];
while (num > 0) {
digits.push(num % 10);
num = parseInt(num / 10);
}
digits.reverse();
console.log(digits);``````

One upside I can see is that you won't have to run `parseInt()` on every digit, you're dealing with the actual digits as numeric values. This is the shortest I've found, though it does return the digits as strings:

``````let num = 12345;

[...num+''] //["1", "2", "3", "4", "5"]
``````

Or use this to get back integers:

``````[...num+''].map(n=>+n) //[1, 2, 3, 4, 5]
`````` ``````// Split positive integer n < 1e21 into digits:
function digits(n) {
return Array.from(String(n), Number);
}

// Example:
console.log(digits(1234)); // [1, 2, 3, 4]`````` A functional approach in order to get digits from a `number` would be to get a `string` from your `number`, split it into an `array` (of characters) and map each element back into a number.

For example:

``````var number = 123456;

var array = number.toString()
.split('')
.map(function(item, index) {
return parseInt(item);
});

console.log(array); // returns [1, 2, 3, 4, 5, 6]
``````

If you also need to sum all digits, you can append the `reduce()` method to the previous code:

``````var num = 123456;

var array = num.toString()
.split('')
.map(function(item, index) {
return parseInt(item);
})
.reduce(function(previousValue, currentValue, index, array) {
return previousValue + currentValue;
}, 0);

console.log(array); // returns 21
``````

As an alternative, with ECMAScript 2015 (6th Edition), you can use arrow functions:

``````var number = 123456;
var array = number.toString().split('').map((item, index) => parseInt(item));
console.log(array); // returns [1, 2, 3, 4, 5, 6]
``````

If you need to sum all digits, you can append the `reduce()` method to the previous code:

``````var num = 123456;

var result = num.toString()
.split('')
.map((item, index) => parseInt(item))
.reduce((previousValue, currentValue) => previousValue + currentValue, 0);

console.log(result); // returns 21
`````` ``````function iterateNumber(N, f) {
let n = N;
var length = Math.log(n) * Math.LOG10E + 1 | 0;
for (let i = 0; i < length; i++) {
const pow = Math.pow(10, length - i - 1)
let c = (n - (n % pow)) / pow
f(c, i)
n %= pow
}
}
`````` I might be wrong, but a solution picking up bits and pieces. Perhaps, as I still learning, is that the functions does many things in the same one. Do not hesitate to correct me, please.

``````const totalSum = (num) => [...num + ' '].map(Number).reduce((a, b) => a + b);
``````

So we take the parameter and convert it to and arr, adding empty spaces. We do such operation in every single element and push it into a new array with the map method. Once splited, we use reduce to sum all the elements and get the total.

As I said, don't hesitate to correct me or improve the function if you see something that I don't.

Almost forgot, just in case:

``````const totalSum = (num) => ( num === 0 || num < 0) ? 'I need a positive number' : [...num + ' '].map(Number).reduce((a, b) => a + b);

``````

If negatives numbers or just plain zero go down as parameters. Happy coding to us all.