Stop an input field in a form from being submitted

I'm writing some javascript (a greasemonkey/userscript) that will insert some input fields into a form on a website.

The thing is, I don't want those input fields to affect the form in any way, I don't want them to be submitted when the form is submitted, I only want my javascript to have access to their values.

Is there some way I could add some input fields into the middle of a form and not have them submitted when the form is submitted?

Obviously the ideal thing would be for the input fields to not be in the form element, but I want the layout of my resulting page to have my inserted input fields appear between elements of the original form.

Answers:

Answer

You could insert input fields without "name" attribute:

<input type="text" id="in-between" />

Or you could simply remove them once the form is submitted (in jQuery):

$("form").submit(function() {
   $(this).children('#in-between').remove();
});
Answer

The easiest thing to do would be to insert the elements with the disabled attribute.

<input type="hidden" name="not_gonna_submit" disabled="disabled" value="invisible" />

This way you can still access them as children of the form.

Disabled fields have the downside that the user can't interact with them at all- so if you have a disabled text field, the user can't select the text. If you have a disabled checkbox, the user can't change its state.

You could also write some javascript to fire on form submission to remove the fields you don't want to submit.

Answer

Simple try to remove name attribute from input element.
So it has to look like

<input type="checkbox" checked="" id="class_box_2" value="2">
Answer

You can write an event handler for onsubmit that removes the name attribute from all of the input fields that you want not to be included in the form submission.

Here's a quick untested example:

var noSubmitElements = [ 'someFormElementID1', 'someFormElementID2' ]; //...
function submitForm() {
    for( var i = 0, j = noSubmitElements.length; i < j; i++ ) {
        document.getElementById(noSubmitElements[i]).removeAttribute('name');
    }
}
form.onsubmit = submitForm;
Answer

Add disabled="disabled" in input and while jquery remove the attribute disabled when you want to submit it using .removeAttr('disabled')

HTML:

<input type="hidden" name="test" value="test" disabled='disabled'/>

jquery:

$("input[name='test']").removeAttr('disabled');

Answer

Handle the form's submit in a function via onSubmit() and perform something like below to remove the form element: Use getElementById() of the DOM, then using [object].parentNode.removeChild([object])

suppose your field in question has an id attribute "my_removable_field" code:

var remEl = document.getElementById("my_removable_field");
if ( remEl.parentNode && remEl.parentNode.removeChild ) {
remEl.parentNode.removeChild(remEl);
}

This will get you exactly what you are looking for.

Answer

Do you even need them to be input elements in the first place? You can use Javascript to dynamically create divs or paragraphs or list items or whatever that contain the information you want to present.

But if the interactive element is important and it's a pain in the butt to place those elements outside the <form> block, it ought to be possible to remove those elements from the form when the page gets submitted.

Answer

You need to add onsubmit at your form:

<form action="YOUR_URL" method="post" accept-charset="utf-8" onsubmit="return validateRegisterForm();">

And the script will be like this:

        function validateRegisterForm(){
        if(SOMETHING IS WRONG)
        { 
            alert("validation failed");
            event.preventDefault();
            return false;

        }else{
            alert("validations passed");
            return true;
        }
    }

This works for me everytime :)

Answer

I just wanted to add an additional option: In your input add the form tag and specify the name of a form that doesn't exist on your page:

<input form="fakeForm" type="text" readonly value="random value" />
Answer

I know this post is ancient, but I'll reply anyway. The easiest/best way I have found is just to simply set the name to blank.

Put this before your submit:

document.getElementById("TheInputsIdHere").name = "";

All in all your submit function might look like this:

document.getElementById("TheInputsIdHere").name = "";
document.getElementById("TheFormsIdHere").submit();

This will still submit the form with all of your other fields, but will not submit the one without a name.

Answer
$('#serialize').click(function () {
  $('#out').text(
    $('form').serialize()
  );
});

$('#exclude').change(function () {
  if ($(this).is(':checked')) {
    $('[name=age]').attr('form', 'fake-form-id');
  } else {
    $('[name=age]').removeAttr('form');    
  }
  
  $('#serialize').click();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="/">
  <input type="text" value="John" name="name">
  <input type="number" value="100" name="age">
</form>

<input type="button" value="serialize" id="serialize">
<label for="exclude">  
  <input type="checkbox" value="exclude age" id="exclude">
  exlude age
</label>

<pre id="out"></pre>
Answer

All of the above answers already said everything about (not) naming the form controls or programmatically removing them before actually submitting your form.

Although, across my research I found one other solution that I haven't seen mentioned in this post:
If you encapsulate the form controls you want to be unprocessed/not sent, inside another <form> tag with no method attribute nor path (and obviously no submit type control like a button or submit input nested in it), then submitting the parent form won't include those encapsulated form controls.

<form method="POST" path="/path">
  <input type="text" name="sent" value="..." />
  <form>
    <input type="text" name="notSent" value="..." />
  </form>
  <input type="submit" name="submit" value="Submit" />
</form>

The [name="notSent"] control value won't be processed nor sent to the server POST endpoint, but the one from [name="sent"] will.

This solution might be anecdotic but I'm still leaving it for posterity...

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