How to grab substring before a specified character jQuery or JavaScript

//split string into an array and grab the first item

var streetaddress = addy.split(',')[0];

Also, I'd recommend naming your variables with camel-case(streetAddress) for better readability.

If you like it short simply use a RegExp:

var streetAddress = /[^,]*/.exec(addy)[0];

almost the same thing as David G's answer but without the anonymous function, if you don't feel like including one.

s = s.substr(0, s.indexOf(',') === -1 ? s.length : s.indexOf(','));

in this case we make use of the fact that the second argument of substr is a length, and that we know our substring is starting at 0.

the top answer is not a generic solution because of the undesirable behavior if the string doesn't contain the character you are looking for.

if you want correct behavior in a generic case, use this method or David G's method, not the top answer

regex and split methods will also work, but may be somewhat slower / overkill for this specific problem.

var streetaddress = addy.substr(0, addy.indexOf('.')); 

(You should read through a javascript tutorial, esp. the part about String functions)

If you want to return the original string untouched if it does not contain the search character then you can use an anonymous function (a closure):

var streetaddress=(function(s){var i=s.indexOf(',');
   return i==-1 ? s : s.substr(0,i);})(addy);

This can be made more generic:

var streetaddress=(function(s,c){var i=s.indexOf(c);
   return i==-1 ? s : s.substr(0,i);})(addy,',');

var newString = string.substr(0,string.indexOf(','));

You could use regex as this will give you the string if it matches the requirements. The code would be something like:

const address = "1345 albany street, Bellevue WA 42344";
const regex = /[1-9][0-9]* [a-zA-Z]+ [a-zA-Z]+/;
const matchedResult = address.match(regex);

console.log(matchedResult[0]); // This will give you 1345 albany street.

So to break the code down. [1-9][0-9]* basically means the first number cannot be a zero and has to be a number between 1-9 and the next number can be any number from 0-9 and can occur zero or more times as sometimes the number is just one digit and then it matches a space. [a-zA-Z] basically matches all capital letters to small letters and has to occur one or more times and this is repeated.

var streetaddress= addy.substr(0, addy.indexOf(',')); 

While it's not the best place for definitive information on what each method does (mozilla developer network is better for that) w3schools.com is good for introducing you to syntax.

var streetaddress = addy.split(',')[0];

try this:

streetaddress.substring(0, streetaddress.indexOf(','));

You can also use shift().

var streetaddress = addy.split(',').shift();

According to MDN Web Docs:

The shift() method removes the first element from an array and returns that removed element. This method changes the length of the array.

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/shift

You can use Azle to get substrings before:

str = 'This is how we go to the place!'

az.get_everything_before(str, 'place')

Result: This is how we go to the

after

str = 'This is how we go to the place!'

az.get_everything_after(str, 'go')

Result: to the place!

and in between:

str = 'This is how we go to the place!'

az.get_everything_between(str, 'how', 'place')

Result: we go to the