How to copy all the attributes of one element and apply them to another?

How do I copy the attributes of one element to another element?

HTML

<select id="foo" class="bar baz" style="display:block" width="100" data-foo="bar">...</select>

<div>No attributes yet</div>

JavaScript

var $div = $('div');
var $select = $('select');

//now copy the attributes from $select to $div

Answers:

Answer

You can use the native Node#attributes property: http://jsfiddle.net/SDWHN/16/.

var $select = $("select");
var $div = $("div");

var attributes = $select.prop("attributes");

// loop through <select> attributes and apply them on <div>
$.each(attributes, function() {
    $div.attr(this.name, this.value);
});

alert($div.data("foo"));
Answer

Pretty Simple

function cloneAttributes(element, sourceNode) {
  let attr;
  let attributes = Array.prototype.slice.call(sourceNode.attributes);
  while(attr = attributes.pop()) {
    element.setAttribute(attr.nodeName, attr.nodeValue);
  }
}
Answer

We could also try extending the jQuery prototype ($.fn) object to provide a new method that can be chained to the jQuery() function.

Here's an extension of @pimvdb's solution to provide a function that copies all attributes

The usage would be like so:

 $(destinationElement).copyAllAttributes(sourceElement);

The extension function can be defined like so:

(function ($) {

    // Define the function here
    $.fn.copyAllAttributes = function(sourceElement) {

        // 'that' contains a pointer to the destination element
        var that = this;

        // Place holder for all attributes
        var allAttributes = ($(sourceElement) && $(sourceElement).length > 0) ?
            $(sourceElement).prop("attributes") : null;

        // Iterate through attributes and add    
        if (allAttributes && $(that) && $(that).length == 1) {
            $.each(allAttributes, function() {
                // Ensure that class names are not copied but rather added
                if (this.name == "class") {
                    $(that).addClass(this.value);
                } else {
                    that.attr(this.name, this.value);
                }

            });
        }

        return that;
    }; 

})(jQuery);

An Example is available at http://jsfiddle.net/roeburg/Z8x8x/

Hope this helps.

Answer

A non-jquery solution:

function copy(element){
    var clone = document.createElement(element.nodeName);
    for(key in element){
        clone.setAttribute(key,element[key]);
    }
    return clone;
}

It copies methods and other stuff you probably don't need, but hopefully you don't mind. This code is small and simple.

Answer

ES6 syntax one liner:

function cloneAttributes(target, source) {
  [...source.attributes].forEach( attr => { target.setAttribute(attr.nodeName ,attr.nodeValue) })
}

And as noted in the first comment - you would probably don't want to copy the source id attribute... so this one will save it as a 'data-id' attribute in case you need a reference.

function cloneAttributes(target, source) {
  [...source.attributes].forEach( attr => { target.setAttribute(attr.nodeName === "id" ? 'data-id' : attr.nodeName ,attr.nodeValue) })
}
Answer

I'm facing same problem and after invested lots of time and effort i am creating thisclone textarea into editable div with same attribute

select.getAttributeNames().forEach(attrName => {
  $(div).attr(attrName, inputData.getAttribute(attrName));
});
Answer

Since Firefox 22, Node.attributes is no longer supported (not implemented by other browsers and removed from the spec). It is only supported on Element (Element.attributes).

Answer
$("div").addClass($('#foo').attr('class'));
Answer

A working solution on jsfiddle

EDIT

Updated jsfiddler

Javascript

$(function(){
    var destination = $('#adiv').eq(0);
    var source = $('#bdiv')[0];

    for (i = 0; i < source.attributes.length; i++)
    {
        var a = source.attributes[i];
        destination.attr(a.name, a.value);
    }
});

HTML

<div id="adiv" class="aclass">A class</div>
<div id="bdiv" class="bclass">B class</div>

That's copying #bdiv attributes to #adiv.

Answer

You can try this:

function copyAttributes(from, to)
{
  $($(from)[0].attributes).
    each(function(){$(to).attr(this.nodeName, this.nodeValue);});

  return $(to);
};

The return statement lets you write things like:

copyAttributes(some_element, $('<div></div>')).append(...) ...

Hope this helps.

Answer

Javascript solution

Copy the attributes of old element to the new element

const $oldElem = document.querySelector('.old')
const $newElem = document.createElement('div')

Array.from($oldElem.attributes).map(a => {
  $newElem.setAttribute(a.name, a.value)
})

Replace the old element with the new element, if required

$oldElem.parentNode.replaceChild($newElem, $oldElem)

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