If you're wondering why am I applying the
JSON.stringify() function to the date, it's because I using local storage to store some data on the client side and use it whenever the client lands on my website again ( it's faster that way rather than making more requests to the server ). That data usually updates once in a while ( I'm grabbing the data through API from another website ), so I set up a
data_update variable and I'm storing it together with the other data.
That way I'm grabbing the stored data from the local storage and check if the difference between
data_update ( which is a date / time ) and the time / date when the check it's made and see if it's greater than a week / day /etc .
So that is the reason why I'm using the JSON functions. My problem is that when I'm parsing the data from the local storage, the date seems to be different from a
I'm trying to do the next operation per say :
var x = JSON.parse(JSON.stringify(new Date())); var y = JSON.parse(this.get_local_storage_data(this.data_cache_key)); // the data object stored on local storage var q = y.data_update; // this is the variable where the Date() was stored console.log(Math.floor((x-q)/1000));
The above will return
null. Also when I want to see the
Math.floor(x) result, it returns
So what can I do in this situation ? Is there a fix for this ?
If you look at the output of JSON.stringify for a Date, you'll see that:
Results in a string. JSON does not have a primitive representation of Date objects that JSON.parse will turn back into a Date object automatically.
The Date object's constructor can take a date string, so you can turn those string values back into dates by doing:
var x = new Date(JSON.parse(JSON.stringify(new Date())));
Then the arithmetic will work.
x = new Date(JSON.parse(JSON.stringify(new Date()))) y = new Date(JSON.parse(JSON.stringify(new Date()))) y - x => 982
Thank God is:
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